document.write( "Question 549294: A picture has a height that is 4/3 its width. It is to be enlarged to have an area of 192 square inches. What will be the dimensions of the enlargement?. \n" ); document.write( "
Algebra.Com's Answer #357595 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! A picture has a height that is 4/3 its width. It is to be enlarged to have an area of 192 square inches. What will be the dimensions of the enlargement?. \n" ); document.write( ": \n" ); document.write( "Let x = the value of the multiplier \n" ); document.write( "then the dimensions of the picture will be: 4x by 3x \n" ); document.write( ": \n" ); document.write( "the area \n" ); document.write( "4x * 3x = 192 \n" ); document.write( "12x^2 = 192 \n" ); document.write( "x^2 = \n" ); document.write( "x^2 = 16 \n" ); document.write( "x = 4 is the multiplier \n" ); document.write( ": \n" ); document.write( "4*4 = 16 is the length \n" ); document.write( "4*3 = 12 is the width \n" ); document.write( " \n" ); document.write( " |