document.write( "Question 549294: A picture has a height that is 4/3 its width. It is to be enlarged to have an area of 192 square inches. What will be the dimensions of the enlargement?. \n" ); document.write( "
Algebra.Com's Answer #357595 by ankor@dixie-net.com(22740)\"\" \"About 
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A picture has a height that is 4/3 its width. It is to be enlarged to have an area of 192 square inches. What will be the dimensions of the enlargement?.
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\n" ); document.write( "Let x = the value of the multiplier
\n" ); document.write( "then the dimensions of the picture will be: 4x by 3x
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\n" ); document.write( "the area
\n" ); document.write( "4x * 3x = 192
\n" ); document.write( "12x^2 = 192
\n" ); document.write( "x^2 = \"192%2F12\"
\n" ); document.write( "x^2 = 16
\n" ); document.write( "x = 4 is the multiplier
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\n" ); document.write( "4*4 = 16 is the length
\n" ); document.write( "4*3 = 12 is the width
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