document.write( "Question 549200: joe is 3/5 as old as brother sam. in 5 years sam will be one and one half times as old as joe.. how old is joe now. \n" ); document.write( "
Algebra.Com's Answer #357586 by mananth(16946)\"\" \"About 
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Sam age ==x
\n" ); document.write( "Joe age = (3/5)x\r
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\n" ); document.write( "\n" ); document.write( "after 5 years
\n" ); document.write( "sam = x+5 years
\n" ); document.write( "Joe = ((3/5)x+5)\r
\n" ); document.write( "\n" ); document.write( "x+5 = (3/2)*(3/5x+5)
\n" ); document.write( "multiply by 2
\n" ); document.write( "2(x+5)=3((3/5)x+5)
\n" ); document.write( "2x+10 = 3(3x+25)/5
\n" ); document.write( "multiply by 5
\n" ); document.write( "10x+50=9x+75
\n" ); document.write( "10x-9x=75-50
\n" ); document.write( "x=25 sam's age
\n" ); document.write( "Joes age 3/5 * 25=15 years\r
\n" ); document.write( "\n" ); document.write( "m.ananth@hotmail.ca
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