document.write( "Question 549200: joe is 3/5 as old as brother sam. in 5 years sam will be one and one half times as old as joe.. how old is joe now. \n" ); document.write( "
Algebra.Com's Answer #357586 by mananth(16946)![]() ![]() You can put this solution on YOUR website! Sam age ==x \n" ); document.write( "Joe age = (3/5)x\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "after 5 years \n" ); document.write( "sam = x+5 years \n" ); document.write( "Joe = ((3/5)x+5)\r \n" ); document.write( "\n" ); document.write( "x+5 = (3/2)*(3/5x+5) \n" ); document.write( "multiply by 2 \n" ); document.write( "2(x+5)=3((3/5)x+5) \n" ); document.write( "2x+10 = 3(3x+25)/5 \n" ); document.write( "multiply by 5 \n" ); document.write( "10x+50=9x+75 \n" ); document.write( "10x-9x=75-50 \n" ); document.write( "x=25 sam's age \n" ); document.write( "Joes age 3/5 * 25=15 years\r \n" ); document.write( "\n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " |