document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=549044>Question 549044</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find the equation of a line through (6,-8), perpendicular to 9y=x-18 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #357580 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=357580\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> find the equation of a line through (6,-8), perpendicular to 9y=x-18<BR>\n" );
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document.write( "Standard form of equation for a straight line{ y=mx+b, m=slope, b=y-intercept.<BR>\n" );
document.write( "9y=x-18<BR>\n" );
document.write( "y=x/9-2<BR>\n" );
document.write( "m=1/9<BR>\n" );
document.write( "..<BR>\n" );
document.write( "slope of perpendicular line =-9 (negative reciprocal of 1/9)<BR>\n" );
document.write( "Equation: <BR>\n" );
document.write( "y=-9x+b<BR>\n" );
document.write( "solve for b using coordinates of given point (6,-8) thru which line passes.<BR>\n" );
document.write( "-8=-9*6+b<BR>\n" );
document.write( "b=54-8=46<BR>\n" );
document.write( "Equation of perpendicular line:<BR>\n" );
document.write( "y=-9x+46 </SPAN>\n" );
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