document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=548078>Question 548078</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If f(x)= 1/2x+6 find the equation of the line for the vertical asymptote and the horizontal asymptote.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #357574 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=357574\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If f(x)= 1/2x+6 find the equation of the line for the vertical asymptote and the horizontal asymptote<BR>\n" );
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document.write( "f(x)= 1/(2x+6)<BR>\n" );
document.write( "To find the vertical asymptote, set the denominator=0, then solve for x.<BR>\n" );
document.write( "2x+6=0<BR>\n" );
document.write( "2x=-6<BR>\n" );
document.write( "x=-3 (Equation of vertical asymptote)<BR>\n" );
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document.write( "If the degree of the numerator is less than the degree of the denominator, as in this case, the horizontal asymptote is the x-axis or y=0. Just by inspection, you should see that as x increases to infinity, f(x) becomes smaller and approaches zero, the x-axis, but never reaches it. </SPAN>\n" );
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