document.write( "Question 547597: write an equation in slope intercept form of a linear function f whose graph passes through (-5,6) and is perpendicular to the line that has an x-intercept of 2 and a y-intercept of 9 \n" ); document.write( "
Algebra.Com's Answer #357573 by lwsshak3(11628)\"\" \"About 
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write an equation in slope intercept form of a linear function f whose graph passes through (-5,6) and is perpendicular to the line that has an x-intercept of 2 and a y-intercept of 9
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\n" ); document.write( "Standard form of equation for a straight line: y=mx+b, m=slope, b=y-intercept
\n" ); document.write( "x-intercept is point (2,0)
\n" ); document.write( "y-intercept is point (0,9)
\n" ); document.write( "These two points are on a straight line,
\n" ); document.write( "Using two points above to find the slope m
\n" ); document.write( "m=∆y/∆x=(9-0)/(0-2)=-9/2
\n" ); document.write( "..
\n" ); document.write( "slope of linear function f, perpendicular to line=2/9 (negative reciprocal)
\n" ); document.write( "Equation: y=(2/9)x+b
\n" ); document.write( "solving for b using given point (-5,6) thru which f passes
\n" ); document.write( "6=(2/9)*-5+b
\n" ); document.write( "6=-10/9+b
\n" ); document.write( "b=6+10/9=54/9+10/9=64/9
\n" ); document.write( "Equation of f: y=2x/9+64/9 \n" ); document.write( "
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