document.write( "Question 549170: angle ABC has vertices A(4,4), B(-1,4), and C(1,6). Find the orthocenter of angle ABC
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Algebra.Com's Answer #357564 by KMST(5328) $\"\"$ $\"About$

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AB is the horizontal line $\"y=4\"$ , so the altitude from point C is the perpendicular (vertical) line through C, $\"x=1\"$ .
\n" ); document.write( "The slope of BC is $\"%286-4%29%2F%281-%28-1%29%29=2%2F%281%2B1%29=2%2F2=1\"$ , so the slope of the (perpendicular) altitude from/through A is $\"-1%2F1=-1\"$ . The altitude is on the line
\n" ); document.write( " $\"y-4=%28-1%29%28x-4%29\"$ ---> $\"y-4=-x%2B4%29\"$ ---> $\"y=-x%2B8\"$
\n" ); document.write( "The intersection of those two altitudes is the intersection of the 3 altitudes, the orthocenter. It's coordinates are $\"x=1\"$ and $\"y=-1%2B8=7\"$
\n" ); document.write( "The orthocenter of triangle ABC is (1,7).
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