document.write( "Question 549205: joe is 3/5 as old as brother sam. in 5 years sam will be one and one half times as old as joe.. how old is joe now. \n" ); document.write( "
Algebra.Com's Answer #357555 by mananth(16946)![]() ![]() You can put this solution on YOUR website! Sam = x years \n" ); document.write( "Joe = (3/5)x\r \n" ); document.write( "\n" ); document.write( "after 5 years\r \n" ); document.write( "\n" ); document.write( "sam= x+5 \n" ); document.write( "Joe = (3/5)x+5\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "multiply by 2 \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "multiply by 5 \n" ); document.write( "5(2x+10)=3(3x+25) \n" ); document.write( "10x+50=9x+75 \n" ); document.write( "10x-9x=25 \n" ); document.write( "x= 25 ===.Sam's age \n" ); document.write( "Joe's age 3/5 * 25 = 15 years\r \n" ); document.write( "\n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " |