document.write( "Question 549191: How many liters of 20% alcohol solution must be mixed with 60 liters of 70% solution to get a 60% solution? \n" ); document.write( "
Algebra.Com's Answer #357521 by mananth(16946)\"\" \"About 
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--------percent ---------------- quantity
\n" ); document.write( "Alcohol I 70 ---------------- 60 L
\n" ); document.write( "Alcohol II 20 ---------------- x L
\n" ); document.write( "Mixture 60 ---------------- 60 + x L
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\n" ); document.write( "70*60+20x=60(60+x)
\n" ); document.write( "4200 + 20 x =3600+60x
\n" ); document.write( "20 x + -60x=3600-4200
\n" ); document.write( "-40 x = -600
\n" ); document.write( "/ -40
\n" ); document.write( "x = 15
\n" ); document.write( " 15 L of Alcohol II
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