document.write( "Question 549191: How many liters of 20% alcohol solution must be mixed with 60 liters of 70% solution to get a 60% solution? \n" ); document.write( "
Algebra.Com's Answer #357521 by mananth(16946)![]() ![]() You can put this solution on YOUR website! --------percent ---------------- quantity \n" ); document.write( "Alcohol I 70 ---------------- 60 L \n" ); document.write( "Alcohol II 20 ---------------- x L \n" ); document.write( "Mixture 60 ---------------- 60 + x L \n" ); document.write( " \n" ); document.write( "70*60+20x=60(60+x) \n" ); document.write( "4200 + 20 x =3600+60x \n" ); document.write( "20 x + -60x=3600-4200 \n" ); document.write( "-40 x = -600 \n" ); document.write( "/ -40 \n" ); document.write( "x = 15 \n" ); document.write( " 15 L of Alcohol II \n" ); document.write( " \n" ); document.write( " |