document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=549165>Question 549165</A>: <I><SPAN STYLE=\"word-break: break-all;\"> One hundred dollars is invested at 12% interest compounded annually. Determine how much the investment is worth after 1 year.\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #357515 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=357515\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Principal P =	100									<BR>\n" );
document.write( "Amount=	A									<BR>\n" );
document.write( "years=n	1									<BR>\n" );
document.write( "compounded	1	times a year		t\r<BR>\n" );
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document.write( "Simple interest & compound Interest for first year are same						<BR>\n" );
document.write( "Rate =	12.00			0.12						<BR>\n" );
document.write( "Amount =P*((n+r)/n)^n*t									<BR>\n" );
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document.write( "Amount =100	*(	1	+	0.12	)^	1	*	1<BR>\n" );
document.write( "Amount =100*(1+0.12)^1			<BR>\n" );
document.write( "	100*(1.12)^	1					<BR>\n" );
document.write( "Amount =	112									<BR>\n" );
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