document.write( "Question 549167: how do you do this?
\n" ); document.write( "Write the slope intercept form of the equation of the line passing through the point (5,-4) and perpendicular to the line y=-4/3x+5
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Algebra.Com's Answer #357511 by mananth(16946)\"\" \"About 
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1 y = -1 1/ 3 x + 5
\n" ); document.write( "Divide by 1
\n" ); document.write( " y = -4/ 3 x + 5
\n" ); document.write( "Compare this equation with y=mx+b, m= slope & b= y intercept
\n" ); document.write( "slope m = -4/3
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\n" ); document.write( "The slope of a line perpendicular to the above line will be the negative reciprocal 3/4
\n" ); document.write( "m1*m2=-1
\n" ); document.write( "The slope of the required line will be 3/4
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\n" ); document.write( "m= 3/4 ,point ( 5 , -4 )
\n" ); document.write( "Find b by plugging the values of m & the point in
\n" ); document.write( "y=mx+b
\n" ); document.write( "-4 = 15/4 + b
\n" ); document.write( "b= -31/4
\n" ); document.write( "m= 3/4
\n" ); document.write( "The required equation isy = 3/ 4x- 31/ 4
\n" ); document.write( "m.ananth@hotmail.ca
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