document.write( "Question 549169: jim is now three times as old as amy. four years ago, jim was seven times as old as amy was then. Find their present ages. \n" ); document.write( "
Algebra.Com's Answer #357510 by oberobic(2304)\"\" \"About 
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J = Jim's age
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\n" ); document.write( "Jim is 3 times as old as Amy.
\n" ); document.write( "J = 3*A
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\n" ); document.write( "Four years ago:
\n" ); document.write( "J-4 = Jim's age
\n" ); document.write( "A-4 = Amy's age
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\n" ); document.write( "Four years ago, Jim was 7 times as old as Amy.
\n" ); document.write( "J-4 = 7*(A-4)
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\n" ); document.write( "Substitute J=3*A
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\n" ); document.write( "3A-4 = 7A - 28
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\n" ); document.write( "3A -7A = -28 + 4
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\n" ); document.write( "-4A = -24
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\n" ); document.write( "A = 6
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\n" ); document.write( "J = 3*A = 3*6 = 18
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\n" ); document.write( "Check how old they were 4 years ago.
\n" ); document.write( "A = 6-4 = 2
\n" ); document.write( "J = 18-4 = 14
\n" ); document.write( "14 = 7*2 ?
\n" ); document.write( "Correct.
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\n" ); document.write( "Answer: Amy is 6, and Jim is 18.
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\n" ); document.write( "Done.
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