document.write( "Question 549129: How many gallons of 80% antifreeze must be added to 90 gallons of 20% antifreeze to get a mixture of 70% antifreeze? \n" ); document.write( "
Algebra.Com's Answer #357482 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! How many gallons of 80% antifreeze must be added to 90 gallons of 20% antifreeze to get a mixture of 70% antifreeze? \n" ); document.write( "------ \n" ); document.write( "alcohol + alcohol = alcohol \n" ); document.write( "0.20*90 + 0.80x = 0.70(90+x) \n" ); document.write( "--- \n" ); document.write( "Multiply thru by 100 to get: \n" ); document.write( "20*90 + 80x = 70*90 + 70x \n" ); document.write( "10x = 50*90 \n" ); document.write( "x = 450 gallong (amt. of 80% solution needed) \n" ); document.write( "====================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "====================== \n" ); document.write( " |