document.write( "Question 549129: How many gallons of 80% antifreeze must be added to 90 gallons of 20% antifreeze to get a mixture of 70% antifreeze? \n" ); document.write( "
Algebra.Com's Answer #357482 by stanbon(75887)\"\" \"About 
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How many gallons of 80% antifreeze must be added to 90 gallons of 20% antifreeze to get a mixture of 70% antifreeze?
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\n" ); document.write( "alcohol + alcohol = alcohol
\n" ); document.write( "0.20*90 + 0.80x = 0.70(90+x)
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\n" ); document.write( "Multiply thru by 100 to get:
\n" ); document.write( "20*90 + 80x = 70*90 + 70x
\n" ); document.write( "10x = 50*90
\n" ); document.write( "x = 450 gallong (amt. of 80% solution needed)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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