document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=549056>Question 549056</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of the base of an isosceles triangle is 10 meters less than twice the length of one of its legs.  If the perimeter of the triangle is 50 meters, find the length of the base of the triangle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #357442 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=357442\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The length of the base of an isosceles triangle is 10 meters less than twice the length of one of its legs. If the perimeter of the triangle is 50 meters, find the length of the base of the triangle.<BR>\n" );
document.write( "**<BR>\n" );
document.write( "let x=length of one of the legs<BR>\n" );
document.write( "2x-10=length of the base<BR>\n" );
document.write( "Perimeter =50=2x+2x-10<BR>\n" );
document.write( "4x=60<BR>\n" );
document.write( "x=15<BR>\n" );
document.write( "2x-10=30-10=20<BR>\n" );
document.write( "ans:<BR>\n" );
document.write( "Base=20 meters </SPAN>\n" );
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