document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=549016>Question 549016</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The pickling company wants to make 1400 liters of a 6% brine(salt) solution by mixing a 15% brine solution with water.  How much of each should be used to accomplish this?\r<BR>\n" );
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document.write( "I thought the equation should look something like 15%B + W = 6% times 1400.  But I can't get that to work. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #357440 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=357440\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The pickling company wants to make 1400 liters of a 6% brine(salt) solution by mixing a 15% brine solution with water. How much of each should be used to accomplish this? <BR>\n" );
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document.write( "let x=liters of 15% solution to mix with water<BR>\n" );
document.write( "1400-x=liters of water to mix with 15% solution<BR>\n" );
document.write( "15%x+0%(1400-x)=6%(1400) <BR>\n" );
document.write( ".15x=.06(1400)<BR>\n" );
document.write( "x=(.06/.15)*1400=560<BR>\n" );
document.write( "1400-x=840<BR>\n" );
document.write( "ans:<BR>\n" );
document.write( "liters of 15% solution to mix with water=560<BR>\n" );
document.write( "liters of water to mix with 15% solution=840 </SPAN>\n" );
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