document.write( "Question 549037: R=p(200 - p), where p equal and less than 200.
\n" ); document.write( "Find R when p = 100
\n" ); document.write( "Find p when R = 7500
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Algebra.Com's Answer #357425 by mathie123(224)\"\" \"About 
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Find R when p = 100\r
\n" ); document.write( "\n" ); document.write( "Subsituting p=100 into R=p(200-p) we get:
\n" ); document.write( "\"R=100%28200-100%29\"
\n" ); document.write( "\"R=100%28100%29\"
\n" ); document.write( "\"R=10000\"\r
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\n" ); document.write( "\n" ); document.write( "Find p when R = 7500
\n" ); document.write( "Substituting R=7500 into R=p(200-p) we get:
\n" ); document.write( "\"7500=p%28200-p%29\"
\n" ); document.write( "\"7500=200p-p%5E2\"
\n" ); document.write( "\"p%5E2-200p-7500=0\"
\n" ); document.write( "We can now use the quadratic formula which says
\n" ); document.write( "\"x=%28-b%2B-sqrt%28b%5E2-4ac%29%29%2F2a\"\r
\n" ); document.write( "\n" ); document.write( "And substituting our values in we get:
\n" ); document.write( "\"p=%28200%2B-sqrt%28200%5E2-4%2A1%2A%28-7500%29%29%29%2F2%2A1\"
\n" ); document.write( "\"p=%28200%2B-sqrt%2840000%2B30000%29%29%2F2\"
\n" ); document.write( "\"p=%28200%2B-sqrt%2870000%29%29%2F2\"
\n" ); document.write( "\"p=%28200%2B-sqrt%284%2A17500%29%29%2F2\"
\n" ); document.write( "\"p=%28200%2B-sqrt%284%29%2Asqrt%2817500%29%29%2F2\"
\n" ); document.write( "\"p=%28200%2B-2%2Asqrt%2817500%29%29%2F2\"
\n" ); document.write( "\"p=%282%28100%2B-sqrt%2817500%29%29%29%2F2\"
\n" ); document.write( "\"p=%28100%2B-sqrt%2817500%29%29\"\r
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