document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=53493>Question 53493</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A merchant blends tea that sells for $3.00 a pound with tea that sells for $2.75 a pound to produce 80 lb of a mixture that sells for $2.90 a pound.  How many pounds of each type of tea does the merchant use in the blend? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #35741 by </B><A HREF=/tutors/aboutme.mpl?userid=bubblz190><B>bubblz190(11)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=bubblz190><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=35741\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Tea 1____Tea 2_____Selling<BR>\n" );
document.write( "$3.00____$2.75_____$2.90<BR>\n" );
document.write( "x lbs__+__80-x__=___ 80 lbs<BR>\n" );
document.write( "3x + 2.75(80-x) = 80 lbs<BR>\n" );
document.write( "3x + 220 - 2.75x = $232 (price of 80lbs)<BR>\n" );
document.write( ".25x = 12<BR>\n" );
document.write( "x = 48\r<BR>\n" );
document.write( "\n" );
document.write( "You need 48 lbs of Tea 1 and 32 lbs(80-48) of Tea 2. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );