document.write( "Question 548969: a picture frame measures 24cm by 15 cm.There is 220 cm squared of picture showing.The frame is of uniform thickness.Find the thickness. \n" ); document.write( "
Algebra.Com's Answer #357362 by mananth(16946)\"\" \"About 
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Area of picture frame =24*15 = 360 m^2\r
\n" ); document.write( "\n" ); document.write( "let the uniform width be x on length & width on each side\r
\n" ); document.write( "\n" ); document.write( "width of picture = 15-2x
\n" ); document.write( "length of picture = 24-2x\r
\n" ); document.write( "\n" ); document.write( "(15-2x)(24-2x)=220\r
\n" ); document.write( "\n" ); document.write( "360-30x-48x+4x^2=220\r
\n" ); document.write( "\n" ); document.write( "360-220-78x+4x^2=0\r
\n" ); document.write( "\n" ); document.write( "4x^2-78x+140=0
\n" ); document.write( "/2
\n" ); document.write( "2(2x^2-39x+70)=0\r
\n" ); document.write( "\n" ); document.write( "2(2x^2-35x-4x+70)=0
\n" ); document.write( "2(2x(x-17.5)-2(2x-35))=0\r
\n" ); document.write( "\n" ); document.write( "2((x-17.5)(x-2))=0\r
\n" ); document.write( "\n" ); document.write( "Neglect 17.5 since it is greater than width
\n" ); document.write( "so width = 2feet\r
\n" ); document.write( "\n" ); document.write( "m.ananth@hotmail.ca\r
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