document.write( "Question 548945: To buy both a new car and a new house, Tina sought two loans totalling $191,610. The simple interest rate on the first loan was 6.3%, while the simple interest rate on the second loan was 8.8%. At the end of the first year, Tina paid a combined interest payment of $16,681.66. What were the amounts of the two loans?\r
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document.write( "How do I set up and answer \n" );
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Algebra.Com's Answer #357321 by mananth(16946)![]() ![]() You can put this solution on YOUR website! Fund A 6.30% per annum ---x \n" ); document.write( "Fund B 8.80% per annum ---y \n" ); document.write( " \n" ); document.write( "x+y=191610 ------------------------1 \n" ); document.write( "6.30%x+ 8.80%y= =$16,681.66 \n" ); document.write( "Multiply by100 \n" ); document.write( "6.3x+8.8y=$1,668,166.00 --------2 \n" ); document.write( " \n" ); document.write( "Multiply (1) by -6.3 \n" ); document.write( "we get \n" ); document.write( " \n" ); document.write( "-6.3x-6.3y=-1207143.00 \n" ); document.write( " \n" ); document.write( "Add this to (2) \n" ); document.write( " \n" ); document.write( "0x+2.5y=$461,023.00 \n" ); document.write( " \n" ); document.write( "divide by2.5 \n" ); document.write( " \n" ); document.write( "y = $184,409.20 investment at 8.80% \n" ); document.write( "Balance $7,200.80 investment at 6.30% \n" ); document.write( "CHECK \n" ); document.write( "$7,200.80 --------- 6.30% ------- $453.65 \n" ); document.write( "$184,409.20 ------- 8.80% ------- $16,228.01 \n" ); document.write( "Total -------------- $16,681.66\r \n" ); document.write( "\n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |