document.write( "Question 548855: Two cars left at an intersection at the same time, one heading north and the other heading west. Later they were exactly 95 miles apart. The car heading west had gone 38 miles less than twice as far as the car headed north. How far has each car traveleld? \n" ); document.write( "
Algebra.Com's Answer #357316 by mananth(16946)\"\" \"About 
You can put this solution on YOUR website!
This is a problem where pythagoras theorem has to be applied\r
\n" ); document.write( "\n" ); document.write( "at any given time the cars are travelling at right angles to each other\r
\n" ); document.write( "\n" ); document.write( "north bound has traveled x miles
\n" ); document.write( "west bound car traveled 2x-38miles\r
\n" ); document.write( "\n" ); document.write( "leg1^2+leg2^2=hypotenuse ^2\r
\n" ); document.write( "\n" ); document.write( "x^2+(2x-38)^2=95^2\r
\n" ); document.write( "\n" ); document.write( "x^2+4x^2-152x+1444=9025\r
\n" ); document.write( "\n" ); document.write( "5x^2-152x-7581=0
\n" ); document.write( "Find the roots of the equation by quadratic formula
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\n" ); document.write( "a= 5 , b= -152 , c= -7581
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\n" ); document.write( "b^2-4ac= 23104 + 151620
\n" ); document.write( "b^2-4ac= 174724 \"%09sqrt%28%09174724%09%29=%09418%09\"
\n" ); document.write( "\"x=%28-b%2B-sqrt%28b%5E2-4ac%29%29%2F%282a%29\"
\n" ); document.write( "\"x1=%28-b%2Bsqrt%28b%5E2-4ac%29%29%2F%282a%29\"
\n" ); document.write( "x1=( 152 + 418 )/ 10
\n" ); document.write( "x1= 57.00
\n" ); document.write( "x2=( 152 -418 ) / 10
\n" ); document.write( "x2= -26.60
\n" ); document.write( "Ignore negative value \r
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\n" ); document.write( "\n" ); document.write( "57 miles north bound car
\n" ); document.write( "west bound car = 2*57-38=76 miles
\n" ); document.write( "m.ananth@hotmail.ca
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