document.write( "Question 548825: C and Y candy company mixes candy that costs $6.00 per kg with candy that costs $4.50 per kg. How many kilograms of each are needed to make ao 3kg box that costs $15.00? \n" ); document.write( "
Algebra.Com's Answer #357313 by mananth(16946)![]() ![]() You can put this solution on YOUR website! $ 6 Candy x kgs \n" ); document.write( "$4.5 candy y kgs\r \n" ); document.write( "\n" ); document.write( "x+y=3....................(1) \n" ); document.write( "6x+4.5y=15................(2)\r \n" ); document.write( "\n" ); document.write( "multiply (1) by -6\r \n" ); document.write( "\n" ); document.write( "-6x-6y=-18 \n" ); document.write( "add to (2) \n" ); document.write( "-1.5y=-3 \n" ); document.write( "/-1.5 \n" ); document.write( "y=2 \n" ); document.write( "x=1 \n" ); document.write( "$ 6 Candy 1 kg \n" ); document.write( "$4.5 candy 2 kgs \n" ); document.write( " \n" ); document.write( " |