document.write( "Question 548825: C and Y candy company mixes candy that costs $6.00 per kg with candy that costs $4.50 per kg. How many kilograms of each are needed to make ao 3kg box that costs $15.00? \n" ); document.write( "
Algebra.Com's Answer #357313 by mananth(16946)\"\" \"About 
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$ 6 Candy x kgs
\n" ); document.write( "$4.5 candy y kgs\r
\n" ); document.write( "\n" ); document.write( "x+y=3....................(1)
\n" ); document.write( "6x+4.5y=15................(2)\r
\n" ); document.write( "\n" ); document.write( "multiply (1) by -6\r
\n" ); document.write( "\n" ); document.write( "-6x-6y=-18
\n" ); document.write( "add to (2)
\n" ); document.write( "-1.5y=-3
\n" ); document.write( "/-1.5
\n" ); document.write( "y=2
\n" ); document.write( "x=1
\n" ); document.write( "$ 6 Candy 1 kg
\n" ); document.write( "$4.5 candy 2 kgs
\n" ); document.write( "
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