document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=548837>Question 548837</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I have a problem like 7 ^ log base 7 x. The question asks me to Simplify the expression using inverse properties. How would I go about doing so? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #357305 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=357305\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I have a problem like 7 ^ log base 7 x. The question asks me to Simplify the expression using inverse properties. How would I go about doing so?<BR>\n" );
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document.write( "In logarithmic form: log7(7^x)=x, which in effect says: log of 7^x to base 7 is x, or log of the base to a power is equal to the power. <BR>\n" );
document.write( "The inverse is the exponential form: base(7) raised to log of number(x)=number(7^x)<BR>\n" );
document.write( "7^x=7^x </SPAN>\n" );
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