document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=548849>Question 548849</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The height of a kite above the ground is four feet less than twice the distance from the person flying the kite to a point directly below the kite. The length of the string to the kite is 68 feet. How high is the kite? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #357301 by </B><A HREF=/tutors/aboutme.mpl?userid=KMST><B>KMST(5328)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=KMST><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=KMST><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=357301\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x ALIGN=MIDDLE  ALT=\"x\"   DISABLED_style= \"max-width:90%; height:auto;\" > be the horizontal distance between the person flying the kite (or more precisely the hand holding the kite string), and the point directly below the kite. <BR>\n" );
document.write( "Then, the height of the kite above the ground is<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2x-4 ALIGN=MIDDLE  ALT=\"2x-4\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "We have to assume that the hand holding the string is at the same level as the ground directly below the kite. Then it would look like this:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=drawing%28200%2C300%2C-8%2C40%2C-5%2C67%2C%0D%0Atriangle%280%2C0%2C32%2C0%2C32%2C60%29%2C+rectangle%2830%2C0%2C32%2C2%29%2C%0D%0Alocate%288%2C3.5%2Chorizontal%29%2Clocate%2815%2C0%2Cx%29%2Clocate%2832.5%2C30%2C2x-4%29%2Clocate%2832.5%2C62%2Ckite%29%2Clocate%28-7.5%2C2%2Chand%29%2Clocate%2810%2C30%2C68%29%0D%0A%29 ALIGN=MIDDLE   DISABLED_style= \"max-width:90%; height:auto;\" > and we would apply Pythagoras theorem to state that <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%5E2%2B%282x-4%29%5E2=68%5E2 ALIGN=MIDDLE  ALT=\"x%5E2%2B%282x-4%29%5E2=68%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "We simplify the equation to get<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%5E2%2B4x%5E2-16x%2B16=4624 ALIGN=MIDDLE  ALT=\"x%5E2%2B4x%5E2-16x%2B16=4624\"   DISABLED_style= \"max-width:90%; height:auto;\" > --> <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=5x%5E2-16x-4608=0 ALIGN=MIDDLE  ALT=\"5x%5E2-16x-4608=0\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "The quadratic formula gives us<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+=+%2816+%2B-+sqrt%2816%5E2-4%2A5%2A%28-4608%29%29%29%2F%282%2A5%29=%2816+%2B-+sqrt%28256%2B92160%29%29%2F10=%2816+%2B-+sqrt%2892416%29%29%2F10=%2816+%2B-+304%29%2F10 ALIGN=MIDDLE   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "We discard the negative solution, because distances are always positive numbers.<BR>\n" );
document.write( "So <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x=%2816%2B304%29%2F10=320%2F10=32 ALIGN=MIDDLE  ALT=\"x=%2816%2B304%29%2F10=320%2F10=32\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "And rhe height of the kite is<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2x-4=2%2A32-4=64-4=60 ALIGN=MIDDLE  ALT=\"2x-4=2%2A32-4=64-4=60\"   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
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