document.write( "Question 548913: how do i solve: log (base 2) 8^x = -3 \n" ); document.write( "

Algebra.Com's Answer #357275 by nerdybill(7384) $\"\"$ $\"About$

You can put this solution on YOUR website!
log (base 2) 8^x = -3
\n" ); document.write( "we can rewrite as:
\n" ); document.write( "log (base 2) (8)^x = -3
\n" ); document.write( "log (base 2) (2^3)^x = -3
\n" ); document.write( "log (base 2) 2^(3x) = -3
\n" ); document.write( "3x = -3
\n" ); document.write( "x = -1
\n" ); document.write( " \n" ); document.write( "

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