document.write( "Question 548906: If a train leaves at 8:00 and is traveling 60 miles an hour and a car leaves 4 hours later and is traveling at 80 miles an hour, when will the car catch up to the train \n" ); document.write( "

Algebra.Com's Answer #357266 by oberobic(2304) $\"\"$ $\"About$

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Start with the basic distance equation:
\n" ); document.write( "d = r*t
\n" ); document.write( ".
\n" ); document.write( "Train:
\n" ); document.write( "d = 60*t
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\n" ); document.write( "Car leaves 4 hours later going in the same direction:
\n" ); document.write( "d = 80*(t-4)
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\n" ); document.write( "When the car overtakes the train, d = d.
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\n" ); document.write( "60t = 80(t-4)
\n" ); document.write( "60t = 80t -320
\n" ); document.write( "-20t = -320
\n" ); document.write( "t = 16
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\n" ); document.write( "In 16 hours the car will catch up.
\n" ); document.write( "8:00 a.m. + 16 hr = 24:00 = midnight
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\n" ); document.write( "Check the distances to make sure they're the same.
\n" ); document.write( "60*16 = 960
\n" ); document.write( "The car travels for only 12 hours.
\n" ); document.write( "80*12 = 960
\n" ); document.write( "Correct.
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\n" ); document.write( "Done. \n" ); document.write( "

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