document.write( "Question 548826: A random sample of health maintenance organizations (HMOs) was selected. For each HMO, the co-payment (in dollars) for a doctor's office visit was recorded. The results are as follows:
\n" ); document.write( "9,11,9,7,8,6,11,10,5,12,5,7,6,12,12,9,7,5,10,11\r
\n" ); document.write( "\n" ); document.write( "Under the assumption that co-payment amounts are normally distributed, find a confidence interval for the mean co-payment amount in dollars. \r
\n" ); document.write( "\n" ); document.write( "Carry your intermediate computations to at least three decimal places. Round your answers to one decimal place. \r
\n" ); document.write( "\n" ); document.write( "a)What is the lower limit of the confidence interval?
\n" ); document.write( "b)What is the upper limit of the confidence interval?
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Algebra.Com's Answer #357258 by stanbon(75887)\"\" \"About 
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A random sample of health maintenance organizations (HMOs) was selected. For each HMO, the co-payment (in dollars) for a doctor's office visit was recorded. The results are as follows:
\n" ); document.write( "9,11,9,7,8,6,11,10,5,12,5,7,6,12,12,9,7,5,10,11
\n" ); document.write( "Under the assumption that co-payment amounts are normally distributed, find a confidence interval for the mean co-payment amount in dollars.
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\n" ); document.write( "sample mean = x-bar = :8.6
\n" ); document.write( "sample std = s = 2.48
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\n" ); document.write( "Carry your intermediate computations to at least three decimal places. Round your answers to one decimal place.
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\n" ); document.write( "Margin of error if confidence = 95%
\n" ); document.write( "ME = 1.96*2.48/sqrt(20) = 1.087
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\n" ); document.write( "a)What is the lower limit of the confidence interval?:x-bar-ME
\n" ); document.write( "b)What is the upper limit of the confidence interval?:x-bar+ME
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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