document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=548819>Question 548819</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the exact perimeter of the rectangle. Then approximate your answer\r<BR>\n" );
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document.write( "side= square root sign 50cm\r<BR>\n" );
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document.write( "bottom= square root sign 72cm </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #357219 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=357219\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find the exact perimeter of the rectangle. Then approximate your answer <BR>\n" );
document.write( "side= square root sign 50cm <BR>\n" );
document.write( "bottom= square root sign 72cm<BR>\n" );
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document.write( "Perimeter = 2(length + width)<BR>\n" );
document.write( "P = 2(sqrt(50) + sqrt(72))<BR>\n" );
document.write( "P = 2(5sqrt(2) + 6sqrt(2))<BR>\n" );
document.write( "P = 2(11sqrt(2))<BR>\n" );
document.write( "Perimeter = 22sqrt(2) cm<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "================== </SPAN>\n" );
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