document.write( "Question 548588: write the equivalence for series 1,3,5,7,11,13... \n" ); document.write( "
Algebra.Com's Answer #357169 by KMST(5328)\"\" \"About 
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Did you skip a 9 in there? As written it is not a sequence/series that you would expect. It's like finding that the correct answer to \"miss America\" in a Jeopardy game is \"If the USSR sent an intercontinental ballistic missile aimed at the US, what would you hope it would do?\"
\n" ); document.write( "I would expect 1, 3, 5, 7, 9, 11, 13, ..., which I would call an arithmetic sequence (not a series), and it includes that 9, between the 7 and the 11. That would make it an arithmetic sequence with a common difference of 2 (where each number is the previous one plus 2).
\n" ); document.write( "I would describe it with the recursive formula \"a%5Bn%5D=a%5Bn-1%5D%2B2\" with \"a%5B1%5D=1\"
\n" ); document.write( "I could also use an explicit formula, such as
\n" ); document.write( "\"a%5Bn%5D=1%2B2%28n-1%29\" or \"a%5Bn%5D=2n-1\"
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