document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=548685>Question 548685</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of two-digit number is 9. The original two-digit number is 27 less than the number formed by reversing the digits. Find the original number </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #357166 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=357166\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> t=the ten digit and u=the units digit.<BR>\n" );
document.write( "t+u=9<BR>\n" );
document.write( "u=9-t<BR>\n" );
document.write( ".<BR>\n" );
document.write( "10u+t-27=10t+u<BR>\n" );
document.write( "10(9-t)+t-27=10t+9-t<BR>\n" );
document.write( "90-10t+t-27=10t+9-t<BR>\n" );
document.write( "63-9t=9t+9<BR>\n" );
document.write( "-18t=-54<BR>\n" );
document.write( "t=3<BR>\n" );
document.write( "u=6<BR>\n" );
document.write( "36 is the original number.<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Ed<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );