document.write( "Question 548690: The length of a rectangle is 5 meters less than twice the width. If the area of the rectangle is 375 square meters, find the dimensions. \n" ); document.write( "
Algebra.Com's Answer #357163 by jim_thompson5910(35256)\"\" \"About 
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\"A=LW\"\r
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\n" ); document.write( "\n" ); document.write( "\"375=%282W-5%29W\"\r
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\n" ); document.write( "\n" ); document.write( "\"375=W%282W-5%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"375=2W%5E2-5W\"\r
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\n" ); document.write( "\n" ); document.write( "\"0=2W%5E2-5W-375\"\r
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\n" ); document.write( "\n" ); document.write( "\"2W%5E2-5W-375=0\"\r
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\n" ); document.write( "\n" ); document.write( "Now use the quadratic formula to solve\r
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\n" ); document.write( "\n" ); document.write( "\"z+=+%28-b%2B-sqrt%28b%5E2-4ac%29%29%2F%282a%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"W+=+%28-%28-5%29%2B-sqrt%28%28-5%29%5E2-4%282%29%28-375%29%29%29%2F%282%282%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"W+=+%285%2B-sqrt%2825-%28-3000%29%29%29%2F%284%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"W+=+%285%2B-sqrt%283025%29%29%2F4\"\r
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\n" ); document.write( "\n" ); document.write( "\"W+=+%285%2Bsqrt%283025%29%29%2F4\" or \"W+=+%285-sqrt%283025%29%29%2F4\"\r
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\n" ); document.write( "\n" ); document.write( "\"W+=+%285%2B55%29%2F4\" or \"W+=+%285-55%29%2F4\"\r
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\n" ); document.write( "\n" ); document.write( "\"W+=+60%2F4\" or \"W+=+-50%2F4\"\r
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\n" ); document.write( "\n" ); document.write( "\"W+=+15\" or \"W+=+-12.5\"\r
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\n" ); document.write( "\n" ); document.write( "So the width is 15 meters and the length is 2(15)-5 = 30-5 = 25 meters\r
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