document.write( "Question 547896: solve 2a+(2/3)=a-(1/3)
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Algebra.Com's Answer #357131 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"2a%2B2%2F3=a-1%2F3\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "\"3%282a%2B2%2Fcross%283%29%29=3%28a-1%2Fcross%283%29%29\" Multiply both sides by the LCD \"3\" to clear any fractions.\r
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\n" ); document.write( "\n" ); document.write( "\"6a%2B2=3a-1\" Distribute and multiply.\r
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\n" ); document.write( "\n" ); document.write( "\"6a=3a-1-2\" Subtract \"2\" from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"6a-3a=-1-2\" Subtract \"3a\" from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"3a=-1-2\" Combine like terms on the left side.\r
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\n" ); document.write( "\n" ); document.write( "\"3a=-3\" Combine like terms on the right side.\r
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\n" ); document.write( "\n" ); document.write( "\"a=%28-3%29%2F%283%29\" Divide both sides by \"3\" to isolate \"a\".\r
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\n" ); document.write( "\n" ); document.write( "\"a=-1\" Reduce.\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So the solution is \"a=-1\"
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