document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=548631>Question 548631</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 15. A can of soda at 90° F. is placed in a refrigerator that maintains a constant temperature of 36°<BR>\n" );
document.write( "F. The temperature T of the soda t minutes after it is placed in the refrigerator is given by<BR>\n" );
document.write( "T(t) = 36 + 54 e^(– 0.058) t<BR>\n" );
document.write( "Find the temperature of the soda 12 minutes after it is placed in the refrigerator. (Round to the nearest degree.) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #357123 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=357123\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> T(t) = 36 + 54 e^(– 0.058) t<BR>\n" );
document.write( "I believe you meant the 't' to be part of the exponent:<BR>\n" );
document.write( "T(t) = 36 + 54 e^(– 0.058t)<BR>\n" );
document.write( ".<BR>\n" );
document.write( "substitute 12 for t and solve:<BR>\n" );
document.write( "T(12) = 36 + 54 e^(– 0.058*12)<BR>\n" );
document.write( "T(12) = 36 + 54 e^(– 0.696)<BR>\n" );
document.write( "T(12) = 36 + 54(.4986)<BR>\n" );
document.write( "T(12) = 36 + 29.9<BR>\n" );
document.write( "T(12) = 62.9<BR>\n" );
document.write( "rounding:<BR>\n" );
document.write( "T(12) = 63 degrees\r<BR>\n" );
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document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );