document.write( "Question 53461: find the slope and y intercept
\n" ); document.write( "is the intercept wher ethe line crosses the asis\r
\n" ); document.write( "\n" ); document.write( "3x+5y+10=0
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Algebra.Com's Answer #35711 by Earlsdon(6294)\"\" \"About 
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One way you can do this is to get the equation into the \"slope-intercept\" form: y = mx + b where m is the slope and b is the y-intercept.\r
\n" ); document.write( "\n" ); document.write( "3x+5y+10 = 0 Subtract 3x from both sides of the equation.
\n" ); document.write( "5y+10 = -3x Now subtract 10 from both sides.
\n" ); document.write( "5y = -3x-10 Finally, divide both sides by 5.
\n" ); document.write( "y = (-3/5)x-2 Compare this with the slope-intercept form.
\n" ); document.write( "y = mx+b and you can see that m = -3/5 This is the slope, and b = -2 This is the y-intercept which is where the line crosses the y-axis.
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