document.write( "Question 548599: What is ordered pair of real numbers (x, y) for which 16^x – 16^y = 192 and 4^x – 4^y = 8 \n" ); document.write( "
Algebra.Com's Answer #357096 by stanbon(75887)\"\" \"About 
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What is ordered pair of real numbers (x, y) for which
\n" ); document.write( "16^x – 16^y = 192
\n" ); document.write( "and 4^x – 4^y = 8
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\n" ); document.write( "Divide the 1st by the 2nd to get:
\n" ); document.write( "4^x+4^y = 24
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\n" ); document.write( "Add that to 4^x-4^y = 8 to get:
\n" ); document.write( "2*4^x = 32
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\n" ); document.write( "4^x = 16
\n" ); document.write( "x = 2
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\n" ); document.write( "Solve for \"y\":
\n" ); document.write( "4^x+4^y = 24
\n" ); document.write( "16 + 4^y = 24
\n" ); document.write( "4^y = 8
\n" ); document.write( "2^(2y) = 2^3
\n" ); document.write( "2y = 3
\n" ); document.write( "y = (3/2)
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\n" ); document.write( "Solution: (2,3/2)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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