document.write( "Question 548074: Jim purchased a Harley Davidson motorcycle for $17,399 in 2004. The value of the motorcycle depreciates at a rate of 13% each year. Which equation models the value of the motorycle x years after 2004?
\n" ); document.write( "A: M(x)=17,399(13)^x
\n" ); document.write( "B:M(x)=17,399(1.13)^x
\n" ); document.write( "C:M(x)=17,399(0.87x)
\n" ); document.write( "D:M(x)=17,399(0.87)^x \n" ); document.write( "

Algebra.Com's Answer #357085 by lwsshak3(11628) $\"\"$ $\"About$

You can put this solution on YOUR website!
Jim purchased a Harley Davidson motorcycle for $17,399 in 2004. The value of the motorcycle depreciates at a rate of 13% each year. Which equation models the value of the motorycle x years after 2004?
\n" ); document.write( "A: M(x)=17,399(13)^x
\n" ); document.write( "B:M(x)=17,399(1.13)^x
\n" ); document.write( "C:M(x)=17,399(0.87x)
\n" ); document.write( "D:M(x)=17,399(0.87)^x
\n" ); document.write( "**
\n" ); document.write( "Since depreciation is a straight line relationship, I would use the formula for a straight line:
\n" ); document.write( "y=mx+b, m=slope, b=y-intercept
\n" ); document.write( "For given problem:
\n" ); document.write( "Depreciation per year=.13*17399≈$2262
\n" ); document.write( "slope m=2262/year
\n" ); document.write( "y-intercept=17399 (at year 1964)
\n" ); document.write( "Equation for value of motorcycle x years after 1964:
\n" ); document.write( "y=-2262x+17,399 \n" ); document.write( "

\n" );