document.write( "Question 53430: solve the equation if possible.
\n" ); document.write( "6/x - 2/x+3 = 3(x+5)/x(x+3)
\n" ); document.write( "i can not figure out how to do this. will you please help thanks \n" ); document.write( "
Algebra.Com's Answer #35708 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
6/x - 2/x+3 = 3(x+5)/x(x+3)
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\n" ); document.write( "Assume you mean:
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\n" ); document.write( "\"6%2Fx+-+2%2F%28x%2B3%29+=+3%28x%2B5%29%2Fx%28x%2B3%29\"
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\n" ); document.write( "Notice that the expression x(x+3) would be the common denominator; each denominator is a factor of x(x+3). If we mult the equation thru by x(x+3) we will effectively get rid of the denominators, we will have:
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\n" ); document.write( "6(x+3) - 2x = 3(x+5)
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\n" ); document.write( "6x + 18 - 2x = 3x + 15
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\n" ); document.write( "6x - 2x - 3x = 15 - 18
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\n" ); document.write( "1x = -3
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\n" ); document.write( "However we find there is a problem here: in the term (x+3), if substitute -3 for x, we have 0 in denominators, a big no-no in algebra. I guess you will have to say there is no solution.
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