document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=548536>Question 548536</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the length of a rectangle is three inches more than the width. The area of the rectangle is 418 inches. find the width of the rectangle </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #357070 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=357070\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> width = w<BR>\n" );
document.write( "length = w+3\r<BR>\n" );
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document.write( "Area = L*W\r<BR>\n" );
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document.write( "w(w+3)=418\r<BR>\n" );
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document.write( "w^2+3w=418<BR>\n" );
document.write( "w^2+3w-418=0<BR>\n" );
document.write( "w^2+22w-19w-416=0<BR>\n" );
document.write( "w(w+22)-19(w+22)=0<BR>\n" );
document.write( "(w+22)(w-19)=0\r<BR>\n" );
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document.write( "w=19 inches which is positive<BR>\n" );
document.write( "Length = 19+3=22 inches<BR>\n" );
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