document.write( "Question 53427: I have exactly 12 coins in my pocket worth exactly $1.00. I might have nickels, dimes, and/or quarters. What combinations of coins might I have? Find all the possibilities.\r
\n" ); document.write( "\n" ); document.write( "n=nickels, d=dimes, q=quarters. I set formula as n+d+q=12 and furthered it to .5n+.10d+.25q=$1.00. I wasn,t sure if I need a third formula or if I was right. I did a process of elimination with coins and came up with these combinations: #1 2q,0d,10n #2 1q,4d,7n #3 0q,8d,4n
\n" ); document.write( "

Algebra.Com's Answer #35706 by aaaaaaaa(138)\"\" \"About 
You can put this solution on YOUR website!
\"system%28n%2Bd%2Bq=12%2C+5n+%2B+10d+%2B+25q+=+100%29\"\r
\n" ); document.write( "\n" ); document.write( "\"n%2Bd%2Bq+=+12\"
\n" ); document.write( "\"n+=+12-d-q\"\r
\n" ); document.write( "\n" ); document.write( "\"5%2812-d-q%29+%2B+10d+%2B+25q+=+100\"
\n" ); document.write( "\"60+%2B+5d+%2B+20q+=+100\"
\n" ); document.write( "\"5d+%2B+20q+=+40\"\r
\n" ); document.write( "\n" ); document.write( "You might have, by increasing number of quarters:\r
\n" ); document.write( "\n" ); document.write( "8 dimes, 4 nickels
\n" ); document.write( "4 dimes, 1 quarter and 7 nickels
\n" ); document.write( "2 quarters and 10 nickels\r
\n" ); document.write( "\n" ); document.write( "So it seems your solution is correct.
\n" ); document.write( "
\n" );