document.write( "Question 548549: The hypotenuse of a right triangle is 16 in. longer
\n" ); document.write( "than the shortest side and 2 in. longer than the remaining side. Find the dimensions of this triangle. What is the length of the shortest side (in inches)?
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Algebra.Com's Answer #357059 by stanbon(75887)\"\" \"About 
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The hypotenuse of a right triangle is 16 in. longer than the shortest side and 2 in. longer than the remaining side. Find the dimensions of this triangle. What is the length of the shortest side (in inches)?
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\n" ); document.write( "Let shortest side be \"x\":
\n" ); document.write( "Then hypotenuse is \"x+16\":
\n" ); document.write( "3rd side is \"x+14\":
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\n" ); document.write( "Equation:
\n" ); document.write( "x^2 + (x+14)^2 = (x+16)^2
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\n" ); document.write( "x^2 + x^2+28x+14^2 = x^2 + 32x + 16^2
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\n" ); document.write( "x^2 - 4x - 60 = 0
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\n" ); document.write( "x^2-10x+6x-60 = 0
\n" ); document.write( "x(x-10)+6(x-10) = 0
\n" ); document.write( "(x-10)(x+6) = 0
\n" ); document.write( "Positive solution:
\n" ); document.write( "x = 10 (shortest)
\n" ); document.write( "x+16 = 26 (hypotenuse)
\n" ); document.write( "x+14 = 24 (3rd side)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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