document.write( "Question 548549: The hypotenuse of a right triangle is 16 in. longer
\n" ); document.write( "than the shortest side and 2 in. longer than the remaining side. Find the dimensions of this triangle. What is the length of the shortest side (in inches)?
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Algebra.Com's Answer #357058 by mananth(16946)\"\" \"About 
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let the hypotenuse be x
\n" ); document.write( "it is 16 in longer than the shortest side
\n" ); document.write( "so shortest side = x-16
\n" ); document.write( "other side = x-2\r
\n" ); document.write( "\n" ); document.write( "By Pythagoras theorem\r
\n" ); document.write( "\n" ); document.write( "(x-2)^2+(x-16)^2=x^2\r
\n" ); document.write( "\n" ); document.write( "x^2-4x+4+x^2-32x+256=x^2
\n" ); document.write( "x^2-36x+260=0
\n" ); document.write( "x^2-26x-10x+260=0
\n" ); document.write( "x(x-26)-10(x-26)=0
\n" ); document.write( "(x-26)(x-10)=0
\n" ); document.write( "x=26 OR 10\r
\n" ); document.write( "\n" ); document.write( "Only 26 is possible\r
\n" ); document.write( "\n" ); document.write( "shortest side = 26-16=10
\n" ); document.write( "other side = 24\r
\n" ); document.write( "\n" ); document.write( "The sides are 10,24,26\r
\n" ); document.write( "\n" ); document.write( "CHECK
\n" ); document.write( "10^2+24^2=676 = 26^2
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