document.write( "Question 53421This question is from textbook
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document.write( ": The width of a rectangle is 6cm less than the length. A second rectangle, with a perimter of 54 cm is 3cm wider and 2 cm shorter than the first. What are the dimensions for each triangle? \n" );
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Algebra.Com's Answer #35703 by aaaaaaaa(138)![]() ![]() ![]() You can put this solution on YOUR website! width of first rectangle = x \n" ); document.write( "length of first rectangle = x+6\r \n" ); document.write( "\n" ); document.write( "width of the second rectangle = x+3 \n" ); document.write( "length of second rectangle = x+4\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Substituting x:\r \n" ); document.write( "\n" ); document.write( "width of first rectangle = x = 10 cm \n" ); document.write( "length of first rectangle = x+6 = 16 cm\r \n" ); document.write( "\n" ); document.write( "width of the second rectangle = x+3 = 13 cm \n" ); document.write( "length of second rectangle = x+4 = 14 cm \n" ); document.write( " |