document.write( "Question 548404: I have an astronomy program that provides information on known comets. They provide only two pieces of information: Perhelion and eccentricity.\r
\n" ); document.write( "\n" ); document.write( " I have gone through a number of books and web pages both for astronomy problems and math problems trying to find out how to find out the length of the major axis.\r
\n" ); document.write( "\n" ); document.write( "I am not very good at working with advanced math (though I have studied some that I needed to use). Please help me with this. Thank you
\n" ); document.write( "

Algebra.Com's Answer #356972 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
I have an astronomy program that provides information on known comets. They provide only two pieces of information: Perhelion and eccentricity.
\n" ); document.write( "I have gone through a number of books and web pages both for astronomy problems and math problems trying to find out how to find out the length of the major axis.
\n" ); document.write( "----
\n" ); document.write( "Draw an ellipse with major axis = 2a
\n" ); document.write( "---------------------------------------
\n" ); document.write( "Put in the center, the focus, and the object at perigee.
\n" ); document.write( "If the focus is the sun:
\n" ); document.write( "perihelion = distance from focus to object = p
\n" ); document.write( "distance of focus from center = c
\n" ); document.write( "Eccentricity = c/a
\n" ); document.write( "======
\n" ); document.write( "a = p + c
\n" ); document.write( "a = p + ae
\n" ); document.write( "a-ae = p
\n" ); document.write( "a(1-e) = p
\n" ); document.write( "a = p/(1-e)
\n" ); document.write( "2a = 2p/(1-e)
\n" ); document.write( "----
\n" ); document.write( "You are given p and e so you can determine major axis = 2a
\n" ); document.write( "===================
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "=============
\n" ); document.write( "
\n" ); document.write( "
\n" );