document.write( "Question 548366: A camper paddles a canoe 2 miles downstream in a river that has a 2-mile-per-hour current. To return to camp, the canoeist travels upstream on a different branch of the river. It is 4 miles long and has a 1-mile-per-hour current. The total trip (both ways) takes 3 hours. Find the average speed of the canoe in still water. \n" ); document.write( "
Algebra.Com's Answer #356956 by mananth(16946)\"\" \"About 
You can put this solution on YOUR website!
boat speed x mph
\n" ); document.write( "current speed downstream 2 mph
\n" ); document.write( "current speed upstream 1
\n" ); document.write( "Distance with current 2 miles
\n" ); document.write( "Distance against current 4 miles
\n" ); document.write( "
\n" ); document.write( "speed with current x + 2 mph
\n" ); document.write( "speed against current x 1 mph
\n" ); document.write( "Total time = 3 hours
\n" ); document.write( "Time with current= 2 /( x + 2 )
\n" ); document.write( "time against current 4 / ( x -1 )
\n" ); document.write( "
\n" ); document.write( "Time with current + time against = 3 hours
\n" ); document.write( "
\n" ); document.write( "2 /( x + 2 ) + 4 /(x -1 ) = 3
\n" ); document.write( "LCD = ( x + 2 )* (x -1 )
\n" ); document.write( "multiply the equation by the LCD
\n" ); document.write( "we get
\n" ); document.write( "2*(x-1)+4(x+2)=3(x^2+1x-2)
\n" ); document.write( "2x-2+4x+8=3X^2+ 3x-6
\n" ); document.write( "6x+6=3x^2+3x+-6
\n" ); document.write( "3x^2-3x -12= 0
\n" ); document.write( "3x^2-3x-12 = 0
\n" ); document.write( "/ 3
\n" ); document.write( "1 X^2 -1 x -4 = 0
\n" ); document.write( "
\n" ); document.write( " Find the roots of the equation by quadratic formula
\n" ); document.write( " a= 1 ,b= -1 ,c= -4
\n" ); document.write( "
\n" ); document.write( " b^2-4ac= 1 + 16
\n" ); document.write( " b^2-4ac= 17
\n" ); document.write( " \"x=%28-b%2B-sqrt%28b%5E2-4ac%29%29%2F%282a%29\" 4.12
\n" ); document.write( " \"x1=%28-b%2Bsqrt%28b%5E2-4ac%29%29%2F%282a%29\"
\n" ); document.write( " \"x1=%28-12%2B21%29%2F%282%29\"
\n" ); document.write( " x1=( 1 + 4.12 )/ 2
\n" ); document.write( " x1= 2.56
\n" ); document.write( " x2=( 1 -4.12 ) / 2
\n" ); document.write( " x2= -1.56
\n" ); document.write( " Ignore negative value
\n" ); document.write( " boat speed = 2.56 mph
\n" ); document.write( " m.ananth@hotmail.ca
\n" ); document.write( "
\n" ); document.write( "
\n" );