document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=546684>Question 546684</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Given the focus of the parabola (0,-6), and the directirx y=6, find the equation of the parabola. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #356953 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=356953\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Given the focus of the parabola (0,-6), and the directirx y=6, find the equation of the parabola.<BR>\n" );
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document.write( "Since the focus is below the directrix on the axis of symmetry,(x=0), this is a parabola which opens downward. Its standard form of equation: (x-h)^2=-4p(y-k), (h,k) being the (x,y) coordinates of the vertex:<BR>\n" );
document.write( "..<BR>\n" );
document.write( "For given parabola:<BR>\n" );
document.write( "y-coordinate of vertex=half-way between directrix and focus on axis of symmetry=0<BR>\n" );
document.write( "x-coordinate of vertex=0<BR>\n" );
document.write( "vertex: (0,0)<BR>\n" );
document.write( "p=distance from vertex to focus or to directrix on the axis of symmetry=6<BR>\n" );
document.write( "Equation of given parabola:<BR>\n" );
document.write( "(x-0)^2=-4p(y-0)<BR>\n" );
document.write( "x^2=-24y (ans) </SPAN>\n" );
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