document.write( "Question 548292: Can you help me solve this equation?\r
\n" ); document.write( "\n" ); document.write( "\"2%2F%28x-3%29%2B2%2Fx=1\"
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Algebra.Com's Answer #356873 by mathie123(224)\"\" \"About 
You can put this solution on YOUR website!
\"2%2F%28x-3%29%2B2%2Fx=1\"
\n" ); document.write( "I don't know about you... but I do not like having fractions... lets get rid of them!
\n" ); document.write( "To do this, we will first multiply every term by x-3 to get
\n" ); document.write( "\"%28x-3%29%2A%282%2F%28x-3%29%29%2B%28x-3%29%2A%282%2Fx%29=%28x-3%29%2A1\"
\n" ); document.write( "\"2%2B%282x-6%2Fx%29=%28x-3%29\"
\n" ); document.write( "Now let's multiply every term by x
\n" ); document.write( "\"x%2A2%2Bx%2A%282x-6%2Fx%29=x%2A%28x-3%29\"
\n" ); document.write( "\"2x%2B2x-6=x%5E2-3x\"
\n" ); document.write( "\"4x-6=x%5E2-3x\"\r
\n" ); document.write( "\n" ); document.write( "This is just a quadratic, so lets put it in the form ax^2+bx+c=0
\n" ); document.write( "\"4x-6-4x%2B6=x%5E2-3x-4x%2B6\"
\n" ); document.write( "\"0=x%5E2-7x%2B6\"
\n" ); document.write( "Now we need to think of two numbers that multiply to our c value (6) and add to our b value (-7) ... if you think hard enough you will find that -1 and -6 does the trick.
\n" ); document.write( "So our equation factors to
\n" ); document.write( "\"%28x-1%29%28x-6%29=0\"\r
\n" ); document.write( "\n" ); document.write( "Now if two things have a product of 0, then at least one of them must be equal to 0
\n" ); document.write( "This means
\n" ); document.write( "\"x-1=0\"
\n" ); document.write( "\"x=1\"
\n" ); document.write( "or
\n" ); document.write( "\"x-6=0\"
\n" ); document.write( "\"x=6\"\r
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\n" ); document.write( "\n" ); document.write( "And there is the two solutions:)
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