document.write( "Question 548009: Aunt Karen is eight years younger than twice the age of Mary. Their ages add up to twenty-eight. Find the ages of Aunt Karen and Mary.
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Algebra.Com's Answer #356841 by Maths68(1474)![]() ![]() You can put this solution on YOUR website! \r \n" ); document.write( "\n" ); document.write( "Let \n" ); document.write( "Present age of Aunt Karen = k \n" ); document.write( "Present age of Mary = m\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Aunt Karen is eight years younger than twice the age of Mary \n" ); document.write( "k+8=2m \n" ); document.write( "k=2m-8..........(1) \n" ); document.write( "Their ages add up to twenty-eight. \n" ); document.write( "k+m=28.........(2) \n" ); document.write( "Put the value of k from (1) to (2) \n" ); document.write( "2m-8+m=28 \n" ); document.write( "3m=28+8 \n" ); document.write( "3m=36 \n" ); document.write( "3m/3=36/3 \n" ); document.write( "m=12 \n" ); document.write( "Put the value of m in (1) \n" ); document.write( "k=2m-8..........(1) \n" ); document.write( "k=2(12)-8 \n" ); document.write( "k=24-8 \n" ); document.write( "k=16\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Present age of Aunt Karen = k = 16 \n" ); document.write( "Present age of Mary = m = 12 \n" ); document.write( " \n" ); document.write( " |