document.write( "Question 548259: From a group of 7 men and 6 women, five persons are to be selected to form a committee so that at least 3 men are there on the committee. In how many ways can it be done ?
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Algebra.Com's Answer #356836 by mathie123(224)\"\" \"About 
You can put this solution on YOUR website!
If there are AT LEAST three men on the committee, this means there could be 4 or 5 men. We will look at each case. \r
\n" ); document.write( "\n" ); document.write( "If there are 3 Men and 2 Women.
\n" ); document.write( "There are \"%287C3%29\" ways to pick the 3 men (note it is a combination as order does not matter).
\n" ); document.write( "There are \"%286C2%29\" ways to pick the 2 women (again, order doesn't matter)
\n" ); document.write( "These two things are done at the same time, so we can use the product rule.
\n" ); document.write( "\"%287C3%29%286C2%29\"\r
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\n" ); document.write( "\n" ); document.write( "If there are 4 men and 1 woman
\n" ); document.write( "There are \"%287C4%29\" ways to pick the 4 men (note it is a combination as order does not matter).
\n" ); document.write( "There are \"%286C1%29\" ways to pick the 1 woman (again, order doesn't matter)
\n" ); document.write( "These two things are done at the same time, so we can use the product rule.
\n" ); document.write( "\"%287C4%29%286C1%29\"\r
\n" ); document.write( "\n" ); document.write( "If it is all men
\n" ); document.write( "There are \"%287C5%29\" ways to pick the 5 men.\r
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\n" ); document.write( "\n" ); document.write( "Now, we can add all these three options up and get our final answer. I will let you do this.
\n" ); document.write( "If you are unsure of answer please feel free to let me know:)
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