document.write( "Question 548215: A shopkeeper finds that the cost C of ordering and storing the latest laptop is
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document.write( "C = 2 x + (300000 / x), where x is in the interval [1, 300]. The delivery of truck can bring at most 300 units per
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document.write( "order.
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document.write( "(a) Find the order size that will minimize the cost
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document.write( "(b) Could the cost be decreased if the truck is replaced with a larger one that could bring 400 units? \n" );
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Algebra.Com's Answer #356820 by htmentor(1343)![]() ![]() You can put this solution on YOUR website! A shopkeeper finds that the cost C of ordering and storing the latest laptop is \n" ); document.write( "C = 2 x + (300000 / x), where x is in the interval [1, 300]. The delivery of truck can bring at most 300 units per \n" ); document.write( "order. \n" ); document.write( "(a) Find the order size that will minimize the cost \n" ); document.write( "(b) Could the cost be decreased if the truck is replaced with a larger one that could bring 400 units? \n" ); document.write( "===================================== \n" ); document.write( "The minimum of the cost function is obtained by taking the derivative and setting=0 \n" ); document.write( "C(x) = 2x + 300000/x \n" ); document.write( "dC(x)/dx = 0 = 2 - 300000/x^2 \n" ); document.write( "Divide through by 2, multiply through by x^2: \n" ); document.write( "0 = x^2 - 150000 \n" ); document.write( "Taking the positive solution, we get x = sqrt(150000) = 387 [to the nearest unit] \n" ); document.write( "(a) However, the truck can deliver at most 300 units. Therefore, the order size which will minimize the cost is 300 units. \n" ); document.write( "(b) Yes. The cost is minimized when the number of units is 387 \n" ); document.write( " |