document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=548209>Question 548209</A>: <I><SPAN STYLE=\"word-break: break-all;\"> two number cubes are rolled. find the probability that the numbers rolled are doubles and have sum that is a multiple of 4 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #356802 by </B><A HREF=/tutors/aboutme.mpl?userid=mathie123><B>mathie123(224)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mathie123><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=356802\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> First off there are 6 numbers to roll on the first die and 6 numbers to roll on the second die.  Therefore there are 6*6=36 total rolls that can be made.\r<BR>\n" );
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document.write( "If the numbers are doubles.  We have the following sums:<BR>\n" );
document.write( "1+1=2<BR>\n" );
document.write( "2+2=4<BR>\n" );
document.write( "3+3=6<BR>\n" );
document.write( "4+4=8<BR>\n" );
document.write( "5+5=10<BR>\n" );
document.write( "6+6=12\r<BR>\n" );
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document.write( "Looking at this we can see that there are 3 possible soubles that have a sum that is a multiple of 3 (2 and 2, 4 and 4, 6 and 6).  <BR>\n" );
document.write( "therefore this probability is <BR>\n" );
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