document.write( "Question 548177: how many quarts of pure antifreeze must be added to 2 quarts of a 20% antifreeze solution to obtain a 50% antifreeze solution? \n" ); document.write( "
Algebra.Com's Answer #356762 by mananth(16946)\"\" \"About 
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--------percent ---------------- quantity
\n" ); document.write( "Antifreeze I 20 ---------------- 2 quarts
\n" ); document.write( "Pure 100 ---------------- x quarts
\n" ); document.write( "Mixture 50 ---------------- 2 + x quarts
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\n" ); document.write( "20*2+100x=50(2+ x)
\n" ); document.write( "40+100x =100+50x
\n" ); document.write( "100x+-50x=100- -40
\n" ); document.write( "50x=60
\n" ); document.write( "/ 50
\n" ); document.write( "x = 1.2
\n" ); document.write( " 1.2 quarts of Pure
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