document.write( "Question 548161: With a tail wind, a jet flew 2000 miles in 4 hours. The jet's return trip against the same wind required 5 hours. Find the jet's speed and the wind speed. I got 500,0. I know that's wrong. \n" ); document.write( "
Algebra.Com's Answer #356744 by mananth(16946)\"\" \"About 
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plane speed speed =x mph
\n" ); document.write( "wind speed =y mph
\n" ); document.write( "against wind , x-y 5 hours
\n" ); document.write( "with wind , x+y 4 hours
\n" ); document.write( "
\n" ); document.write( "Distance = same= 2000 miles
\n" ); document.write( "t=d/r against wind
\n" ); document.write( "2000/(x-y)=5.00
\n" ); document.write( "5(x-y)=2,000.00
\n" ); document.write( "With wind
\n" ); document.write( "5x-5y=2000 ....................1
\n" ); document.write( "2000/(x+y)=4.00
\n" ); document.write( "4.00(x+y)=2000
\n" ); document.write( "4.00x+4y=2000 ...............2
\n" ); document.write( "Multiply (1) by 4.00
\n" ); document.write( "Multiply (2) by 5.00
\n" ); document.write( "we get
\n" ); document.write( "20 x + -20 y = 8000
\n" ); document.write( "20 x + 20 y = 10000
\n" ); document.write( "40 x = 18000
\n" ); document.write( "/ 40
\n" ); document.write( "x = 450 mph
\n" ); document.write( "
\n" ); document.write( "plug value of x in (1)
\n" ); document.write( "5 x -5 y = 2000
\n" ); document.write( "2250 -5 y = 2000
\n" ); document.write( "-5 y = 2000 -2250
\n" ); document.write( "-5 y = -250
\n" ); document.write( " y = 50 mph
\n" ); document.write( " plane speed 450 mph
\n" ); document.write( " wind 50 mph
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\n" ); document.write( "m.ananth@hotmail.ca
\n" ); document.write( " \n" ); document.write( "
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